Ok so on problem 27 in the hw for tonight the answer is -2+_ sr i2/3
when I solved the problem I got -2+_ sr i19 / 3
as you can see the only thing I had simplified differently was the 38, can some on please help me

On the daily quiz to day many of us forgot how to factor out problems like...
(x+3)^3. All you do to solve these problems is set up the problem so it looks like (x+3) (x+3) (x+3), next you factor the first (x+3) in to the second (x+3) giving you (x+3) (x^2+6x+9). Than distribute the last (x+3) throughout.
x^3+6x^2+9x+3x^2+18x+27
combine like terms and your answer is...
x^3+9x^2+27x+27

While doing the HW problems today I forgot that terms like (x+5)^2 are written as (x+5)(x+5) - I was writing the problem as x^2+25. This is a small but critical error that could make all the difference on the up coming test.
That's all...Weeeeerd Up!

Today we talked about real life examples of functions, so here's a few to help you guys grasp the concept.

The amount of air pollution is dependent on the number of cars on the road.

The distance a baseball is hit depends on the force it is struck with.

A person's hunger is dependent on the the amount of food they have recently consumed.

( time is always the independent variable because nothing can control time.)

Just vocab...Expanding is the same thing as Foiling.

WEDNESDAY, MARCH 16, 2011

I found this problem a little confusing on the class/home work today but, with some help, was able to figure it out.
4z^2+4zw+w^2 factored the problem looks like...
(2z+w)(2z+w) simplify to look like...
(2z+w)^2
I realize that this is not a difficult problem, but I thought the problem was not a perfect of squares.

Today we learned about SPECIAL CASES, the two kinds of special cases are...
1. x^2+2xy+y^2 factored this problem will always look like (x+y)(x+y), the problem starts and ends with a perfect square.
2. x^2-y^2 factored the problem looks like (x+y)(x-y)
COOL

Today in class I was asked to explain a home work problem to the class, here are some terms that I should have used:
4x^2-4x-15
4x=the leading coefficient
-15=the constant

Also to help clairify:
Standard Quadratic Method- the set up looks like ax^2+bx+c
Just incase anyone missed that in class.
TANKS!!!

Helpful tip for factoring.
2y^3+8y^2-10y we can make this problem have aleading coeficient of one by simply extracting 2y from the first term.
2y(y^2+4y-5) now just factor
2y(y-5)(y-1) thats all, word up!!!

(3x+2)(x-4)-(3x+2)(x+8) this is a binomial not a polynmial.
(3x+2)(x-4)-(x+8)simlify by foiling
(3x+2)(-12)distribute the negative sign and combine the last two terms
-12(3x+2) fully factored!

adding polynomials

When adding polynomials you can only add numbers and variables with the same exponents.

For Example: (3a^5-9a^3+4a^2) + (-8a^5+8a^3+2)
3a^5+(-8a^5)-9a^3+8a^3+4a^3+4a^2+2
= -5a^5-a^3+4a^2+2