Expanding the walls of our classroom. This is an interactive learning ecology for students and parents in our Algebra 2 class. This ongoing dialogue is as rich as YOU make it. Visit often and post your comments freely.
Sunday, October 31, 2010
Danielle, Inequalities
http://www.blogger.com/post-create.g?blogID=2979614811124141785
Saturday, October 30, 2010
When One Side of Inequality is Divided by a Value
6a + 3 < -3
-4
First multiply both sides by -4
6a + 3(-4) < -3(-4)
6a + 3 > 12
Now subtract 3 from both sides to isolate the coefficient
6a - 3 > 12 -3
6a > 9
Now divide 6 from both sides to isolate the variable
6a > 9
6 6
a > 2/3
graph!
--(--------------------->
2/3
Harrison siad...
the intersect would be {a, c}
Friday, October 29, 2010
A2A (2011): Tyler, September 10
Tuesday, October 26, 2010
B.O.B. Chapter 3
I am going to offer you up to 5 bonus points on your test with completion of a simple assignment. I would like you to post your reflections on the material covered so far. Just comment on this post. To get that bonus on your test, the kind of post I'd like you to make should have one or more of these characteristics:
- A reflection on a particular class (like the first paragraph above-how did that class enhance your learning?).
- A reflective comment on your progress in the course.
- A comment on something that you've learned that you thought was "cool".
- A comment about something that you found very hard to understand but now you get it! Describe what sparked that "moment of clarity" and what it felt like.
- Have you come across something we discussed in class out there in the "real world" or another class? Describe the connection you made.
Absolute Value Symbol
Amelia
Monday, October 25, 2010
Chapter 3 Test Monday November 1st
Tutorial design team to be named soon!
Sunday, October 24, 2010
Scribe Post
In class today we talked more about how to solve compound inequalities with AND or OR. This is review from chapter 3 section 2.
Solving With And
1st treat both sides of the inequality like its own problem, so solve for both sides.
X+1<> 3
X <> 5
2nd Because the inequalities are joined by AND the solution will include all numbers between 8 and 5.
On a graph the problem would look like this: ___(___________)___
5 8
This shows that your answer is all numbers between 5 and 8.
Solving With OR
1st solve both sides of the problem individually.
6X – 4 < 2X or -3x < -9
-4 < -4X or X < 1
1>X or X > 3
2nd since the solution set are joined with OR the solution will include all the numbers either one of the two inequalities in step 1
Here’s how the problem looks in graph form: X>3 or X<1 color="#cc0000">+++++)+(+++++++++>
1 3
Because X can be all numbers less than one it can also be written as: (-∞, 1)
Because X can be all numbers greater than three it can also be written as: (3, ∞ )
Note: ( ) = < >
[ ] = ≤ ≥
4X ≤ 12
X ≤ 4
This can also be written as: (-∞, 4]
Ok, good stuff Next scribe will be Cole.
Friday, October 22, 2010
Website for help and explinations x
http://mathforum.org/library/drmath/drmath.high.html
Danielle, Interval Notation - Here is an easier way of understanding intervals
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Thursday, October 21, 2010
Sribe Post For October 21 2010
Chapter 3 section 1
9. 4x + 1 ≥ 21 - solve and give answer in both interval and graph forms
First step: clear fractions- there are no fractions
Second step: simplify each side separately- both sides are already simplified
Third step: isolate the variable terms on one side. 4x + 1 ≤ 21
4x ≤ 20
Fourth step:isolate the variable- 4x ≥ 20
4x/4 ≥ 20/4
x ≥ 5
The answer in graph form: <-|-|-|-|-|-|-|-|-|-|-[-|-|-|-|-> and in interval form: [5, ∞)
-5 0 9
Now that we know have to solve the inequalities lets move a bit faster.
22. m-2(m-4) ≤ 3m
m-2m-8≤3m
-m-8≤ 3m
-m-8 + -m ≤ 3m + -m
8 ≤ 2m
4 ≤ m
Lets now try a different type of problem form the hw.
Solve the linear equation
31. 5(x+3)-2(x-4)=2(x+7)
Simplifying
5(x + 3) + -2(x + -4) = 2(x + 7)
Reorder the terms:
5(3 + x) + -2(x + -4) = 2(x + 7)
(3 * 5 + x * 5) + -2(x + -4) = 2(x + 7)
(15 + 5x) + -2(x + -4) = 2(x + 7)
Reorder the terms:
15 + 5x + -2(-4 + x) = 2(x + 7)
15 + 5x + (-4 * -2 + x * -2) = 2(x + 7)
15 + 5x + (8 + -2x) = 2(x + 7)
Reorder the terms:
15 + 8 + 5x + -2x = 2(x + 7)
Combine like terms: 15 + 8 = 23
23 + 5x + -2x = 2(x + 7)
Combine like terms: 5x + -2x = 3x
23 + 3x = 2(x + 7)
Reorder the terms:
23 + 3x = 2(7 + x)
23 + 3x = (7 * 2 + x * 2)
23 + 3x = (14 + 2x)
Solving
23 + 3x = 14 + 2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2x' to each side of the equation.
23 + 3x + -2x = 14 + 2x + -2x
Combine like terms: 3x + -2x = 1x
23 + 1x = 14 + 2x + -2x
Combine like terms: 2x + -2x = 0
23 + 1x = 14 + 0
23 + 1x = 14
Add '-23' to each side of the equation.
23 + -23 + 1x = 14 + -23
Combine like terms: 23 + -23 = 0
0 + 1x = 14 + -23
1x = 14 + -23
Combine like terms: 14 + -23 = -9
1x = -9
Divide each side by '1'.
x = -9
Simplifying
x = -9
<-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|->
-10 0 7
Ok lets try something a bit different again.
Solve each inequality, giving its solution set in both interval and graph forms.
37.-4 <>6
First step: add 5 on both sides of the inequality
-4 + 5 < x < 11
Second step: simplify- 1
<-|-|-|-|-|-|-[-|-|-|-|-|-|-|-|-|-]-|-|>
-5 9 13 0 9 13
Even if my wonderful scribe post did not help you maybe this guy with a power point can. =)
http://www.youtube.com/watch?v=MJ4dCBmYwvU
Just copy paste the "ULR" into your browser address bar
For the next scribe i choice Harrison
Wednesday, October 20, 2010
Section 3.1, Ifeayani
inequality- A statement between two expressions indicating which one has greater value.
solving a compound inequality with “and”
ex1: x+19 and x-23
step1: solve each inequality in the compound inequality individually.
x+19 and x-23
x8 x5
step2:Since the inequalities are joined with and, the solution set of the compound inequality will include all numbers that satisfy both inequalities in step 1 (the intersection of the solution sets).
[-----------]
|-|-|-|-|-|-|-|-|-|-|-|-
0 2
ex2: 2x+1 7 and 3x-4 17
(subtract 1) 2x 6 3x 21
(divide by 2) x 3 and x 7
set notation: [3,7]
solving a compound inequality with or
you solve step 1 the same way but your answer has to include everything that satisfies either equation.
ex1 with “or” would be all real numbers
ex2 with “or” would also be all real numbers
Things To Remember!

Useful Facts to remember while doing a compound inequality:
Example 1: Solve for 3 x + 2 < style="font-style: italic; ">x – 5 > –11
Solve each inequality separately. Since the joining word is “and,” this indicates that the overlap or intersection is the desired result.
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x < style="font-style: italic; ">x > –3 indicates all the numbers to the right of –3. The intersection of these two graphs is all the numbers between –3 and 4. The solution set is
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Another way this solution set could be expressed is
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When a compound inequality is written without the expressed word “and” or “or,” it is understood to automatically be the word “and.” Reading { x | − 3 < x < style="font-style: italic; ">x” position, you say (reading to the left), “ x is greater than –3 and (reading to the right) x is less than 4.” The graph of the solution set is shown in Figure 1 .
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Chapter Three More Symbols
A circle that is filled in means that the number is included in the solution.
A circle that is not filled in and just the outline of a circle means that the number is not included in the solution.
Amelia
Symbols in Chapter 3
< is less than
> is greater than
< with a line underneith it is less than or equal to
> with a line underneith it is greater than or equal to
Sorry I couldnt figure out how to put the line under the sign.
Amelia
Monday, October 18, 2010
Danielle Scribe Post Chapter 3 Section 3.1
2 Test Problems
#11. John has 20 ounces of a 20% of salt solution, How much salt should he add to make it a 25% solution?
concentration= 20%=.20
amount= 20 ounces =20
added= x
Equation for solving problem #11 :
(.20)20 + 1x = .25(20+x)
4 + x = 5 + .25 x
.75x = 1
x= 1/.75
x=4/3 oz.
#12. A tank has a capacity of 10 gallons. When it is full, it contains 15% alcohol. How many gallons must be replaced by an 80% alcohol solution to give 10 gallons of 70% solution?
Equation for solving #12 :
1.5 -. 15x + .80x = 7
After solving this equation you should get
x=8.46 gallons
Next we went over some of Section 3.1, mainly interval notation
and set notation
example of interval notation
x > -1
example of set notation
( -1, infinity symbol)
We did a problem in class to help us distinguish interval notation from set notation
4x-5 > 13
+5 +5
4x/4 > 18/4
x> 9/2
interval notaion
[9/2 , infinity symbol]
set notation
the next scribe :Ifeanyi
New Symbols Used in Chapter 3
Sunday, October 17, 2010
How to Figure out Commission?
commission- a sum or percentage allowed to agents, sales representatives , etc.
commission salary- the money you are paid when you sell a service or product for a company
Tuesday, October 12, 2010
Emma, 3.1 Linear Inequalities in One Variable
An Inequality is whether (or not) the left side equals the right side.
Inequality Symbols:
> less than
< greater than
≤ less than or equal to
≥ greater than or equal to
≠ not equal to
≈ approximately equal to
You CAN NOT include ∞ (infinity) because it never ends.
As an example, JoJo showed that Hana's height (5'3") is less than Christine's height (5'7")
Hana's height < Christine's height
But if Hana's height ≤ Christine's height
Hana could be 5'6" if the inequality were true
Solve for x:
4x - 5 ≥ 13
Add 5 to both sides
4x + 0 ≥ 18
4x ≥ 18
Divide 4 from both sides
4x/4 ≥ 18/4
x ≥ 9/2 Interval notation
•-----|----|----|--> Number line
9/2 5 6 7
[9/2, ∞)
^ ^ not included
included } Set notation
Don't forget to CHECK!
4(5) - 5 ≥ 13
20 - 5 ≥ 13
15 ≥ 13 Yes, the inequality is true.
We don't have any homework over the break.
The next scribe will be Danielle.
Thursday, October 7, 2010
Scribe Post
Section 2.1
Recognizing Conditional Equations, Identities, and Contradictions
1.Conditional
One solution
Final line is x=a number
2. Contradiction
None; solution set is 0 with a / threw it
Final line is false, such as -15=120
3. Identity
Infinite; solution set, all real numbers
Final line is true, such as 0=0
Section 2.2
Solving for a Specified Variable
Example: Solve for t.
prt=I
(pr)t=I associative property
(pr)t/pr=I/pr divide by pr.
t=I/pr
Steps for solving for a Specified Variable
Step 1: Transform so that all terms contain the specified variable are on one side of the equation and all terms without that variable are on the other side.
Step 2: If necessary, use the distributive property to combine the terms with the specified variable. The result should be the product of a sum or the difference and the variable.
Step 3: Divide each side y the factor that is the coefficient of the specified variable.
Section 2.3
It's important to remember how to translate words to mathmatical expressions.
*This was explained on Christines scribe post earlier this week.
Remember the Difference Between Expression and Equation
Expression:
Example: x=5
Equation:
Example: x+2=4
Solving an Investment Problem
Example:
After winning the state lottery, Mark LeBeau has $40,00 to invest. He will put part of the money in an account paying 4% interest and the remainder into stocks paying 6% interest. His accountant tells him that the total annual income from these investments should be $2,040. How much should he invest at each rate?
Step 1: Reas the problem again. We must find the two amounts.
Step 2: Assign a variable
Let x= the amount to invest at 4%
Let 40,000-x= the amount to invest at 6%
The formula for interest is I=prt. Here the time, t, is one year. Make a table to organize the given information.
You can look up the table for this equation on page 82 in your math book.
Step 3: Write an equation. We do so without clearing decimals.
.04+.06(40,000-x)=2040
Step 4: Solve the equation. We do so without clearing decimals.
.04+.06(40,000)-.06x=204o Distributive Property
.04x+2,400-.06x=20 Multiply
-.02x+2,400=2,040 Combine Like Terms
-.02x=-360 Subtract 2,400
x=18,00 Divide by -.02
Step 5: State the answer. Mark should invest $18,000 at 4%. At 6%, he should invest $40,000-$18,000=$22,000.
Step 6: Check bby finding the annual interest at each rate; they should total $2,040.
.04($18,000)=$720 and .06($22,000)=$1,320
$720+$1,320=$2,040, as required.
The Next Scribe Post will be done by Emma
Who founded algebra
Monday, October 4, 2010
BoB -Blogging on Blogging Chapter 2
I am going to offer you up to 5 bonus points on your test with completion of a simple assignment. I would like you to post your reflections on the material covered so far. Just comment on this post. To get that bonus on your test, the kind of post I'd like you to make should have one or more of these characteristics:
- A reflection on a particular class (like the first paragraph above-how did that class enhance your learning?).
- A reflective comment on your progress in the course.
- A comment on something that you've learned that you thought was "cool".
- A comment about something that you found very hard to understand but now you get it! Describe what sparked that "moment of clarity" and what it felt like.
- Have you come across something we discussed in class out there in the "real world" or another class? Describe the connection you made.