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Thursday, October 21, 2010

Sribe Post For October 21 2010

In class today we just did homework that was suppose to be done yesterday night, so i am just going to redo a couple of different hw problems that we did in class today.
Chapter 3 section 1

9. 4x + 1 ≥ 21 - solve and give answer in both interval and graph forms
First step: clear fractions- there are no fractions
Second step: simplify each side separately- both sides are already simplified
Third step: isolate the variable terms on one side. 4x + 1 ≤ 21
4x ≤ 20
Fourth step:isolate the variable- 4x ≥ 20
4x/4 ≥ 20/4
x ≥ 5
The answer in graph form: <-|-|-|-|-|-|-|-|-|-|-[-|-|-|-|-> and in interval form: [5, ∞)
-5 0 9
Now that we know have to solve the inequalities lets move a bit faster.
22. m-2(m-4) ≤ 3m
m-2m-8≤3m
-m-8≤ 3m
-m-8 + -m ≤ 3m + -m
8 ≤ 2m
4 ≤ m
Lets now try a different type of problem form the hw.
Solve the linear equation
31. 5(x+3)-2(x-4)=2(x+7)

Simplifying

5(x + 3) + -2(x + -4) = 2(x + 7)

Reorder the terms:

5(3 + x) + -2(x + -4) = 2(x + 7)

(3 * 5 + x * 5) + -2(x + -4) = 2(x + 7)

(15 + 5x) + -2(x + -4) = 2(x + 7)

Reorder the terms:

15 + 5x + -2(-4 + x) = 2(x + 7)

15 + 5x + (-4 * -2 + x * -2) = 2(x + 7)

15 + 5x + (8 + -2x) = 2(x + 7)

Reorder the terms:

15 + 8 + 5x + -2x = 2(x + 7)

Combine like terms: 15 + 8 = 23

23 + 5x + -2x = 2(x + 7)

Combine like terms: 5x + -2x = 3x

23 + 3x = 2(x + 7)

Reorder the terms:

23 + 3x = 2(7 + x)

23 + 3x = (7 * 2 + x * 2)

23 + 3x = (14 + 2x)

Solving

23 + 3x = 14 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.

23 + 3x + -2x = 14 + 2x + -2x

Combine like terms: 3x + -2x = 1x

23 + 1x = 14 + 2x + -2x

Combine like terms: 2x + -2x = 0

23 + 1x = 14 + 0

23 + 1x = 14

Add '-23' to each side of the equation.

23 + -23 + 1x = 14 + -23

Combine like terms: 23 + -23 = 0

0 + 1x = 14 + -23

1x = 14 + -23

Combine like terms: 14 + -23 = -9

1x = -9

Divide each side by '1'.

x = -9

Simplifying

x = -9

<-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|->

-10 0 7


Ok lets try something a bit different again.

Solve each inequality, giving its solution set in both interval and graph forms.

37.-4 <>6

First step: add 5 on both sides of the inequality

-4 + 5 < x < 11

Second step: simplify- 1


<-|-|-|-|-|-|-[-|-|-|-|-|-|-|-|-|-]-|-|>

-5 9 13 0 9 13

Even if my wonderful scribe post did not help you maybe this guy with a power point can. =)




http://www.youtube.com/watch?v=MJ4dCBmYwvU

Just copy paste the "ULR" into your browser address bar


For the next scribe i choice Harrison









5 comments:

  1. for some reason the computer keeps on changing problem 37 to be incorrect it should read
    -4 < x-5 < 6
    and the number line should look like this
    <-|-|-|-|-|-|-[-|-|-|-|-|-|-|-|-|-]-|-|>
    -5 0 9 13

    ReplyDelete
  2. This comment has been removed by the author.

    ReplyDelete
  3. This comment has been removed by the author.

    ReplyDelete
  4. again for some reason the computer messed up my graph.

    <-|-|-|-|-|-|-[-|-|-|-|-|-|-|-|-|-]-|-|>
    -5___________________13

    ReplyDelete
  5. this was really helpful. good job

    ReplyDelete

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