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Thursday, September 30, 2010

Ike, 2.3, Solving a Mixture Problem

Today was relatively brief in its lesson as due to a technical failure (?) of homework from the previous night. We did cover how to SOLVE A MIXTURE PROBLEM!, though, and so I shall review over this amazingly fun and wildly interesting material for you. Yay!

MIXTURE PROBLEM:
James has 20 ounces of a 20% salt solution. How much salt should he add to make it a 25% solution?

Step One: Set up a table for salt.


original

added

result

concentration




amount





Step Two:
Fill in the table with information given in the question.

John has 20 ounces of a 20% of salt solution. How much salt should he add to make it a 25% solution?

The salt added is 100% salt, which is a 1 in decimal form.
Then you can go ahead and change the rest of the percents to decimal form for easier simplifying. I mean, you dont HAVE to, but thats how i know how to do it. Great!

Then let x= amount of salt added. You get 20 +x.


original

added

result

concentration

0.2

1

0.25

amount

20

x

20 + x



Step 3
:
Multiply down each column.


original

added

result

concentration

0.2

1

0.25

amount

20

x

20 + x

multiply

0.2 × 20

1 × x

0.25(20 + x)


Step 4: original + added = result

0.2 × 20 + 1 × x = 0.25(20 + x)
4 + x = 5 + 0.25x

Isolate variable x
x
– 0.25x = 5 – 4
0.75x = 1
x=4/3


Answer: He's got to add 4/3 ounces of salt. YAY!


um.. next scribe... amelia? I dont know! aaahhh dont hate me.



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