Expanding the walls of our classroom. This is an interactive learning ecology for students and parents in our Algebra 2 class. This ongoing dialogue is as rich as YOU make it. Visit often and post your comments freely.
Sure I will help you! :) for g(x)=1-x^2 you solve the problem as if it is telling you that f(x)=y so what I did on the test to make it easier for myself I plugged numbers in like for the previous problems where they gave you an x value. so what you do is. g(-2)=-(-2)^2+1 g(x)=-3 and you can test different values to... x= -2,0,2 y= -3,1,-3 and then you would know it was a funtion. Does that help?
AAAH you beat me to it. I had just finished the answer then my computer deleted it so had to do it again. When I signed in your comment came up. I'll post mine anyway.
Sure I will help you! :)
ReplyDeletefor g(x)=1-x^2
you solve the problem as if it is telling you that f(x)=y so what I did on the test to make it easier for myself I plugged numbers in like for the previous problems where they gave you an x value.
so what you do is.
g(-2)=-(-2)^2+1
g(x)=-3
and you can test different values to...
x= -2,0,2
y= -3,1,-3
and then you would know it was a funtion. Does that help?
AAAH you beat me to it. I had just finished the answer then my computer deleted it so had to do it again. When I signed in your comment came up. I'll post mine anyway.
ReplyDeletef(x)=3x Substitute values for x
x=1
f(x)=3(1)
f(x)=3
(1,3)
x=2
f(x)=3(2)
f(x)=6
(2,6)
x=0
f(x)=3(0)
f(x)=0
(0,0)
Now graph all of those points.
Its ok we answered both of her questions haha! And you answered mine!
ReplyDeletethank you SO MUCH! Haha I was so confused what was going onn!
ReplyDeletethanks amelia for posting the answer to this, because i needed help with this problem also!
ReplyDelete