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Wednesday, April 27, 2011

10.3 solving equations in quadratic form

2(4m-3)^2+7(4m-3)+5=0
2u^2+7u+5=0 let 4m-3=u
(2u+5)(u+1)=0 factor zero factor prop.
2u+5=0 or u+1=0


u=-5/2 or u=-1

4m-3=-5/2 or 4m-3=-1 substitute 4m-3 for u

4m=1/2 or 4m=2 solve for m

m=1/8 or m=1/2

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