b^2-4ac > 0, we have 2 distinct, real solutions
b^2-4ac = 0, there is 1 real solution (double root)
b^2-4ac < 0, there are 0 real solutions
Ex. Find the discriminant of each equation, then, determine the number of real solutions.
a. 2x^2+4x+1=0
ax^2+bx+c
a=2,b=4,c=1
(4)^2-4(2)(1)
16-8=8
2 real solutions.
b. 2x^2+4x+2=0
ax^2+bx+c
a=2,b=4,c=2
(4)^2-4(2)(2)
16-16=0
There is 1 real solution
c. 2x^2+4x+3=0
ax^2+bx=c
a=2,b=4,c=3
(4)^2-4(2)(3)
16-24=-8
There are 0 real solutions
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